Răspuns:
Explicație pas cu pas:
2a) a={0,2,4,6,8,}
fractiile sunt 320/214 ; 322/214 ; 324/214; 326/214 ; 328/214
b)(3x-1)/2=10 3x-1=20 3x=21 x=7
3
a)1212/2323=12·101/23·101=12/23
b)1+2+3+...+100=100·101/2=50·101
202-201+200-199+.....+4-3+2-1=(202-201)+(200-199)+.....+(4-3)+(2-1)=
=1×101=101
50·101/101=50
c)[10(a+b)+(b+a)]/4(a+b)=11(a+b)/4(a+b)=11/4
d) (1+2+2²+....+2^99+1)/2^99=[(2^99-1)/(2-1)+1]/2^99=
=(2^99-1+1)/2^99=1
