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cum se rezolva
[tex] \frac{1}{2 } + ( \frac{1}{2} ) \div ( \frac{1}{3} + \frac{1}{6} ) = \\ \\ \frac{13}{25 } \div \frac{26}{75} + ( \frac{3}{2} ) {}^{2} \times \frac{10}{27} = [/tex]


Răspuns :

Răspuns:

Explicație pas cu pas:

[tex]\frac{1}{2} + (\frac{1}{2}) : (\frac{1}{3} + \frac{1}{6}) = \\\\\frac{1}{2} + (\frac{1}{2}) : (\frac{2}{6} + \frac{1}{6}) =\\\\\frac{1}{2} + (\frac{1}{2}) : \frac{3}{6} = \\\\\frac{1}{2} + (\frac{1}{2}) * \frac{6}{3} =\\\\\frac{1}{2} + \frac{6}{6} =\\\\\frac{3}{6} + \frac{6}{6} =\\\\\frac{9}{6} = \frac{3}{2}[/tex]

[tex]\frac{13}{25} : \frac{26}{75} + (\frac{3}{2})^{2} * \frac{10}{27} =\\\\\frac{13}{25} * \frac{75}{26} + \frac{9}{4} * \frac{10}{27} =\\\\\frac{3}{2} + \frac{5}{6} =\\\\\frac{9}{6} + \frac{5}{6} =\\\\\frac{14}{6} = \frac{7}{3}[/tex]

Sper ca te-am ajutat!!
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