Răspuns:
3[tex]x^{2}[/tex]-8x+5=0
3[tex]x^{2}[/tex]-3x-5x+5=0
3x(x-1)-5(x-1)=0
(x-1)(3x-5)=0
x-1=0, 3x-5=0
x=1, x=[tex]\frac{5}{3}[/tex]
2. A. [tex]x^{2}[/tex]-2x+1=0
[tex](x-1)^{2}[/tex]=0
x-1=0
x=1, A fals
B. [tex]x^{2}[/tex]+4x+3=0
[tex]x^{2}[/tex]+3x+x+3=0
x(x+3)+x+3=0
(x+3)(x+1)=0
x+3=0⇒x1=-3
x+1=0⇒x2=-1
C. [tex]4x^{2}[/tex]-4x+1=0
[tex](2x-1)^{2}[/tex]=0
2x-1=0
2x=1
x=[tex]\frac{1}{2}[/tex]
D. [tex]2x^{2}[/tex]-7x+5=0
[tex]2x^{2}[/tex]-2x-5x+5=0
2x(x-1)-5(x-1)=0
(x-1)(2x-5)=0
x-1=0⇒x1=1
2x-5=0⇒x2=[tex]\frac{5}{2}[/tex]
