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44. Amplificați cu x - 2 raportul 2x+1\x
unde x€R\{0,2}.


Răspuns :

Răspuns:

[tex]\large\bf \!{^{^{^{^{^{^{\displaystyle (x-2)\big)}}}}}}}\!\!\!\dfrac{2x+1}{x}=\dfrac{(x-2)\cdot (2x+1)}{(x-2)\cdot x}=\dfrac{(2x^{2}+x-4x-2)}{x^{2}-2x}=\dfrac{(2x^{2}-3x-2)}{x^{2}-2x}[/tex]

==pav38==