Răspuns: Ai mai jos rezolvarea
Explicație pas cu pas:
Buna!
[tex]\large\bf \bigg(\dfrac{7}{9} \bigg)^{0}=\dfrac{7^{0}}{9^{0}}=\dfrac{1}{1}=1[/tex]
[tex]\bf[/tex]
[tex]\large\bf \bigg(\dfrac{31}{51} \bigg)^{1}=\dfrac{31^{1}}{51^{1}}=\dfrac{31}{51}[/tex]
[tex]\bf ~~~[/tex]
[tex]\large\bf \bigg(\dfrac{2^{5}}{16}\cdot \dfrac{3}{6} \bigg)^{50}=\bigg(\dfrac{2^{5}}{2^{4}}\cdot \dfrac{\not3}{\not 6} \bigg)^{50}=\bigg(\dfrac{\not2^{5}}{\not2^{4}}\cdot \dfrac{1}{2} \bigg)^{50}=\bigg(\dfrac{2}{1}\cdot \dfrac{1}{2} \bigg)^{50}=\bigg(\dfrac{\not2}{\not2} \bigg)^{50}=1^{50}=\boxed{\Large\bf 1}[/tex]
PS: Daca esti pe telefon, te rog sa glisezi spre dreapta pentru a vedea rezolvarea completa
==pav38==
