Răspuns:
Explicație pas cu pas:
[tex]\large \bf c)~~\dfrac{11}{12}+ \dfrac{5}{\boxed{}}=\dfrac{31}{12}[/tex]
[tex]\large \bf \dfrac{5}{\boxed{}}=\dfrac{31}{12} - \dfrac{11}{12}[/tex]
[tex]\large \bf \dfrac{5}{\boxed{}}=\dfrac{20}{12}\implies \large \bf 5\cdot 12 = \boxed{}\cdot 20[/tex]
[tex]\large \bf 60 = \boxed{}\cdot 20 ~~~\bigg|:20[/tex]
[tex]\color{red}\Large \bf \boxed{\bf \boxed{}=3}[/tex]
[tex]\it~~[/tex]
[tex]\large \bf d)~~\dfrac{\boxed{}}{3}+ \dfrac{13}{18}=\dfrac{19}{18}[/tex]
[tex]\large \bf ~\dfrac{\boxed{}}{3} =\dfrac{19}{18}-\dfrac{13}{18}[/tex]
[tex]\large \bf ~\dfrac{\boxed{}}{3} =\dfrac{6}{18}[/tex]
[tex]\large \bf \boxed{} \cdot 18 = 3\cdot 6[/tex]
[tex]\large \bf \boxed{} \cdot 18 = 18~~~~\bigg|:18[/tex]
[tex]\color{red}\Large \bf \boxed{\bf \boxed{}=1}[/tex]
==pav38==
