Răspuns:
[tex]-\frac{1}{2} -\frac{1}{3} +[(-\frac{1}{6}+(+\frac{1}{12})]= \\\\Avem [(-\frac{1}{6}+(+\frac{1}{12})], amplifici-prima- fractie -cu -2- si- o -sa-ti -dea \frac{-2+1}{12} , adica (-\frac{1}{12}). \\Ne- intoarcem -la- primele- doua -fractii-, anume -\frac{1}{2}-\frac{1}{3} -\frac{1}{12} \\Amplificam- prima -fractie -cu -6 si- a -doua- cu- 4. Rezultat: -\frac{6+4+1}{12}=-\frac{11}{12}[/tex]
[tex](-\frac{7}{36})+[(-\frac{2}{9} )+(-\frac{5}{18})-(+\frac{1}{2})]\\(-\frac{7}{36})+(-\frac{2}{9}-\frac{5}{18} +\frac{1}{2})\\Revenim-la-cele-3-fractii-din-acea-parantea-si-amplificam-prima-cu-2-si-a-treia-cu-9. Vom-avea:\\(-\frac{7}{36} )+\frac{-4-5+9}{18} = (-\frac{7}{36} )+0(pentru-ca-0-supra-18-da-0)\\=(-\frac{7}{36} )[/tex]
Sper ca n-am omis nimic, este prima data cand folosesc aceasta rubrica numita "ecuatii". Cineva sa-mi spuna totusi daca e bine ce-am facut...:)
