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8. Adevărat sau fals?
[tex]3x - 2 \leqslant 0 < = > 2 - 3x \geqslant 0 \\ x {}^{2} + 1 > 0 < = > (x + 1) {}^{2} < 0[/tex]
va rog frumos dau corona​


Răspuns :

1 ADEVARAT

[tex]3x - 2 \leqslant 0 | \times ( - 1) \\ - 3x + 2 \geqslant 0 \\ 2 - 3x \geqslant 0 [/tex]

2 FALS

[tex](x + 1) {}^{2} = {x}^{2} + 2x + {1}^{2} [/tex]