Explicație pas cu pas:
T. Pitagora
[tex] {bc}^{2} = {ab}^{2} + {ac}^{2} [/tex]
[tex] {bc}^{2} = {20}^{2} + {15}^{2} [/tex]
[tex] {bc}^{2} = 400 + 225 = 625[/tex]
[tex]bc = \sqrt{625} = \sqrt{ {25}^{2} } = 25[/tex]
[tex]p = ab + ac + bc = 20 + 15 + 25 = 60[/tex]
[tex]a = (ac \times ab ) \div 2 = 20 \times 15 \div 2 = 150[/tex]
b)
[tex] \sin(b) = \frac{ac}{bc} = \frac{20}{25} = \frac{4}{5} [/tex]
[tex] \sin(c) = \frac{ab}{bc} = \frac{15}{25} = \frac{3}{5} [/tex]
[tex] \cos(b) = \frac{ab}{bc} = \frac{15}{25} = \frac{3}{5} [/tex]
[tex] \tan(c) = \frac{ab}{ac} = \frac{15}{20} = \frac{3}{4} [/tex]
