[tex]\it 0.(6)=\dfrac{\ 6^{(3}}{9}=\dfrac{2}{3}[/tex]
Exercițiul se poate scrie:
[tex]\it \Big(\dfrac{\dfrac{3}{2}}{\dfrac{2}{3}}+3\Big)\cdot\dfrac{1}{4}=\Big(\dfrac{3}{2}\cdot\dfrac{3}{2}+3\Big)\cdot\dfrac{1}{4}=\Big(\dfrac{9}{4}+3\Big)\cdot\dfrac{1}{4}=\dfrac{21}{4}\cdot\dfrac{1}{4}=\dfrac{21}{16}[/tex]
