Răspuns:
a.tgB=AC/AB
2=6/AB
2AB=6
AB=6/2=3
Aplici teorema lui pitagora si aflii BC
BC²=AB²+AC²=
3²+6²=9+36=45
BC=√45=√9*5=3√5
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b) sinB=AC/BC
12/13=AC/13
AC=13*12/13=12
Aplici Pitagora si aflii AB
BC²=AB²+AC²
13²=AB²+12²
169=AB²+144
169-144=AB²
25=AB²
AB=√25=5
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c. aplici pitagora si aflii BC
BC²=AB²+AC²
BC²=3²+(3√3)²=9+9*3=
9+27=36
BC=√36=6
sinB=AC/BC
sinB=3√3/6=√3/2
Explicație pas cu pas:
