Răspuns:
[tex]\bf \underline{Mn^{+4}}O_2^{-2}+H_2^{+1}S^{+6}O_4^{-2}+K^{+1} \underline{ \underline{I^{-1}}}\rightarrow \underline{Mn^{+2}}S^{+6}O_4^{-2}+K_2^{+1}S^{+6}O_4^{-2}+H_2^{+1}O^{-2}+ \underline{ \underline{I_2^0}}[/tex]
[tex]\bf Mn^{+4}\xrightarrow{+2} Mn^{+2}|\cdot2\!\!\!/ |1\:\:\: reducere[/tex]
[tex]\bf 2I^{-1}\xrightarrow{-2} I_2^0|\cdot2\!\!\!/ |1\:\:\: oxidare[/tex]
Nu avem coeficienți din egalarea redox, așa că vom egala algebric.
MnO₂+2H₂SO₄+2KI→MnSO₄+K₂SO₄+2H₂O+I₂
