Răspuns:
15mol 15mol 15mol
CH4 + cL2---> CH3CL+HCl
25mol 2x25mol 25mol
CH4 + 2Cl2----> CH2Cl2+ 2HCL
35mol 3x35mol 35mol
CH4 + 3Cl2----> CHCl3 + 3HCl
25mol
CH4 netransformat
la 100mol CH4 sunt necesari (15+50+105)mol Cl2
raportul este 10/17
niu=100molCh4
m=niuxM=100X16g=1600gCH4
1600gCH4..........170molCl2
320g.........................x
x= niu= 34mol Cl2
V= niuxVm= 34x22,4 l =761,6 lCl2
1600g CH4..................25mol CH2Cl2
320g.......................................x
x= 5mol
M=85g/mol----> m= 5x85g=425g CH2Cl2
Explicație:
