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vă rog repede dau coroană ,b) sin² 45°+cos² 45° și Tg 45° tg
c) sin² 60° + cos² 60° și Tg 60° ​


Răspuns :

Sin²45+cos²45=1

Tg45=sin45/cos45=1

Sin²60+cos²60=1

Tg60=sin60/cos60=rad(3)

Obs: sin45=cos45=rad(2)/2

Sin60=rad(3)/2

Cos60=1/2

[tex] \sin {}^{2} 45 + \cos {}^{2} 45 = 1[/tex]

[tex]aplicam \: formula \: \sin {}^{2} x + \cos {}^{2} x = 1[/tex]

[tex]tg45 = \frac{ \sin45 }{ \cos45 } [/tex]

[tex]tg45 = \frac{ \frac{ \sqrt{2} }{2} }{ \frac{ \sqrt{2} }{2} } = 1[/tex]

[tex]aplicam \: formula \: tgx = \frac{ \sin \: x }{ \cos \: x } [/tex]

[tex] \sin {}^{2}60 + \cos {}^{2} 60 = 1[/tex]

[tex]aplicam \: formula \: \sin {}^{2} {x + \cos }^{2} x = 1[/tex]

[tex]tg60 = \frac{ \sin60 }{ \cos60} [/tex]

[tex]tg60 = \frac{ \frac{ \sqrt{3} }{2} }{ \frac{1}{2} } [/tex]

[tex]tg60 = \frac{ \sqrt{3} }{2} \div \frac{1}{2} [/tex]

[tex]tg60 = \frac{ \sqrt{3} }{2} \times \frac{2}{1} = \sqrt{3} [/tex]

[tex]aplicam \: formula \: tgx = \frac{ \sin \: x }{ \cos \: x } [/tex]