Răspuns:
[tex]c) {2}^{18} \times {12}^{18} \div ( {6}^{16} \times {4}^{16} ) = \\ (2 \times 12) {}^{18} \div (6 \times 4) {}^{16} = \\ {24}^{18} \div {24}^{16} = {24}^{2} \\ \\ d) {75}^{38} \div {25}^{38} - ( {3}^{19} ) {}^{2} \\ (75 \div 25) {}^{38} - {3}^{38} = \\ {3}^{38} - {3}^{28} = 0 \\ \\ e) {26}^{27} \div {13}^{27} \div {2}^{5 {}^{2} } = \\ (26 \div 13) {}^{27} \div {2}^{25} = \\ {2}^{27} \div {2}^{25} = {2}^{2} \\ \\ f) {10}^{64} \div {2}^{64} - {5}^{4 {}^{3} } = \\ (10 \div 2) {}^{64} - {5}^{64} = \\ {5}^{64} - {5}^{64} = 0[/tex]
sper că te-am ajutat
