[tex](336+\frac{x+2}{44}-\frac{111+222+333\cdot2}{3})\cdot2=7 \\ 2\cdot336+2\cdot\frac{x+2}{44}-2\cdot \frac{333+666}{3}=7 \\ 672+\frac{x+2}{22}-2\cdot333=7 \\ 672+\frac{x+2}{2}-666=7 \\ 6+\frac{x+2}{2}=7 \\ \frac{x+2}{2}=7-6=1 \\ x+2=2 \\ \Rightarrow \bold{x=0}[/tex]