Răspuns:
1010g KNO₃
Explicație:
M(KNO₃) = A(K) + A(N) + 3 × A(O) = 39 + 14 + 3 × 16 = 101 g/mol
M(HNO₃) = A(H) + A(N) + 3 × A(O) = 1 + 14 + 3 × 16 = 63 g/mol
630g x
K₂CO₃ + 2HNO₃ → 2KNO₃ + H₂O + CO₂↑
2×63g 2×101g
x = 630 × 2 × 101 : (2 × 63) = 1010g KNO₃
-Mihai