3 la puterea -1 + 1 =

[tex] {3}^{ - 1} + 1 = \\ = 0.(3) + 1 = \\ = 0 \frac{3}{9} +1 = \\ = \frac{3}{9} + \frac{9}{9} = \\ = \frac{3 + 9}{9} = \\ = \frac{12 {}^{(3} }{9 {}^{(3} } = \\ = \frac{4}{3} [/tex]