Răspuns:
De fiecare data aplici formula
∫x^αdx=x^(α+1)/(α+1)+c
a)∫x^4dx α=4
F(x)=x^5/5+c
------------------------
b)∫8x^7 dx =8∫x^7dx α=7
F(x)=8*x^8/8+c=x^8+c
---------------------------
c)∫x^(4/5)dx= α=4/5
F(x)=x^(4/5+1)/(4/5+1)=5x^(9/5)/9
---------------------------------------
∫√x^3dx=∫x^(3/5)dx
α=3/5
F(x)=x^(3/5+1)/(3/5+!)+c=
x^8/5/(8/5)=5/8*x^8/5
______________________
∫x^(-8/3)dx
α=-8/3
Aplici aceiasi metoda ca mai sus
Explicație pas cu pas:
