sa se afle a+b unde a=4V×(-3V2)+25 si b=8V27:(2V3)-13

Răspuns:
[tex]a = 4 \sqrt{2} \times ( - 3 \sqrt{2} ) + 25 = - 12 \times 2 + 25 = - 24 + 25 = 1 \\ b = 8 \sqrt{27} \div (2 \sqrt{3}) - 13 = 4 \sqrt{9} - 13 = 4 \times 3 - 13 = 12 - 13 = - 1 \\ a + b = 1 + ( - 1) = 1 - 1 = 0[/tex]