Răspuns:
Explicație pas cu pas:
3) a) a = ? c = 36 ; r = 28 ; i = 32
a : 32 = 36 rest 28 => a = 32·36 + 28 = 1180
b) b = ? r = 7 ; c = 29 ; i = 49
b : 49 = 29 rest 7 => b = 49·29 + 7 = 1428
4) a) x : 6 = 13 + rest ; restul < 13 => r = {0 ; 1 ; 2.....; 12}
x = 6·13 + r => x = {78 ; 79 ; 80 ; 81 ; 82 ; 83 ; ......90}
b) y : 8 = c + r ; c = 5 ; r < 5 => r = {0 ; 1 ; 2 ; 3 ; 4}
y = 8·5+r => y = {40 ; 41 ; 42 ; 43 ; 44}
Suma = 40+41+42+43+44+45 = 85+85+85 = 255
c) z : 7 = c + r ; r < 7 => r = {0 ; 1 ; 2 ; 3 ; 4 ; 5 ; 6}
10:7 = 1 rest 3
11:7 = 1 rest 4
12:7 = 1 rest 5
13 : 7 = 1 rest 6
14 : 7 = 2 rest 0
15 : 7 = 2 rest 1
...........................
97 : 7 = 13 rest 6
98 : 7 = 14 rest 0
99 : 7 = 14 rest 1
suma tuturor resturilor = 3+4+5+6+(13-2+1)·(0+1+2+3+4+5+6) + 6+0+1
= 18+12·21 +7 = 25+252 = 277
