nu bagati in seama cerinta cu nr nat nenule,DAU COROANA

Răspuns:
[tex] {1 }^{2} + {2}^{x } + {3}^{y } < 4[/tex]
REZOLVARE:
[tex] {1}^{2} + {2}^{1 } + {3}^{0} < 4[/tex]
[tex]1 + 2 + 0 < 4[/tex]
[tex]3 < 4[/tex]