1.
A intersectat cu B = (2003; 2014]
2.
[tex] | - 3| + | - 5| \times 2[/tex]
3+5×2= 3+10= 13
3.
NU INTELEG CERINTA
4.
a= 2-4
a= -2
b= 3-9
b= -6
c= 4-16
c= -12
c<b<a
-12; -6; -2
5.
[tex]a = (3 + \sqrt{6} ) {}^{2} + (3 - \sqrt{6} ) {}^{2} [/tex]
[tex]a = \sqrt{(3 + \sqrt{6} ) {}^{2} } + \sqrt{(3 - \sqrt{6} ){}^{2} } [/tex]
[tex]a = |3 + \sqrt{6} | + |3 - \sqrt{6} | [/tex]
a=0
0 =N => a apartine lui N
LA 3 NU INTELEG CERINTA!
MULT SUCCES LA TEZA :))
