Răspuns:
a) 2Al + 3Cl2 → 2AlCl3
b) MCl2=2×35,5=71g/mol
n=m/M
m=n×M=3×71=213g
MAl=27g/mol
2×27g.........3×71g
2Al + 3Cl2 → 2AlCl3
xg..................213g
x=213×2×27/3×71= calculeaza
2moli...........3moli
2Al + 3Cl2 → 2AlCl3
ymoli..............3moli
y=3×2/3=calculeaza
Explicație: