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calculeaza radical din 3+2x=4
[tex] \sqrt{3 + 2 \times = 4} [/tex]


Răspuns :

[tex]\it \sqrt{3+2x}=4 \Rightarrow (\sqrt{3+2x})^2=4^2 \Rightarrow 3+2x=16|_{-3} \Rightarrow 2x=13 \Rightarrow \\ \\ \Rightarrow x=13:2 \Rightarrow x=6,5[/tex]