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Răspuns :

[tex]\it \dfrac{^{\sqrt3+1)}1}{\ \ \sqrt3-1}+\dfrac{^{\sqrt3-1)}1}{\ \ \sqrt3+1}=\dfrac{\sqrt3+1}{(\sqrt3)^2-1^2}+\dfrac{\sqrt3-1}{(\sqrt3)^2-1^2}=\dfrac{\sqrt3+1+\sqrt3-1}{3-1}=\\ \\ \\ =\dfrac{2\sqrt3}{2}=\sqrt3.[/tex]